[ODE] Balance of torque
Gib Bogle
bogle at ihug.co.nz
Tue Aug 3 09:23:31 MST 2004
I think I can now answer my own question (that was quick!). It seems to
be a matter of the timestep size. The period of revolution in the
current case is about 4 sec. I thought that dt=0.01 would be small
enough, but I find that if I reduce it to dt=0.001 the ratio of the
torques becomes 40:39, and presumably reducing dt still further will
further reduce the discrepancy.
Gib
Gib Bogle wrote:
> I'm simulating the motion of a heavy rope spinning about a vertical
> axis. The rope is represented as a number of rods connected by
> ball-and-socket joints, and the two ends are connected to the vertical
> axis by hinge joints. The motion is driven by external applied forces
> on the rods. A constant rotational speed is maintained by suitable
> application of a resisting torque (applied as a force in each
> timestep) on one of the rods that is hinged to the axis (the other is
> free).
>
> The behaviour looks fine, but there is a discrepancy in the torque
> balance. Since the rotational speed is held almost constant, the net
> torque of the applied forces, averaged over one rotation, should match
> the resisting torque, averaged in the same way. (There is no air
> drag.) In fact these two average torques are roughly in the ratio 43:38.
>
> I'd like to know the explanation for this discrepancy, and also if
> there is a way to reduce it.
> Thanks
> Gib
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